Question

find the value of k for which is x=2 is the root of quadratic equation kx2 +x-6=0​

Answer 1

Step-by-step explanation:

If x=2 is a root of the given equation then we have,

=k(2)^2+(2)-6=0

=4k+2-6=0

=4k-4=0

=4k=4

=k=1

Hence, value of k is 1 if x=2 is the root of quadratic equation kx^2 +x-6=0

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