find the value of k for which is x=2 is the root of quadratic equation kx2 +x-6=0
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Step-by-step explanation:
If x=2 is a root of the given equation then we have,
=k(2)^2+(2)-6=0
=4k+2-6=0
=4k-4=0
=4k=4
=k=1
Hence, value of k is 1 if x=2 is the root of quadratic equation kx^2 +x-6=0
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