Question

Find the value of k for which (k+2), 2k, (2k+3) are three consecutive terms of an AP.​

Answer 1

Step-by-step explanation:

as we know that of a b c are in A.P. then 2b=c+a

compare values of the given equation with a b c

a=k+2

b=2k

c=2k+3

according to the question

2(2k)=2k+3+k+2

4k=3k+5

k=5

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