Question

find the value of K for which (k-2) x square + 2(2k -3) x+(5x-6)=0 has equal roots

Answer 1

11kx^2 -5x + k = 0 a = k, b = -5, c = k To have equal roots, b^2 - 4ac = 0 (-5)^2 - 4(k)(k) = 0 25 - 4k^2 = 0 5^2 - (2k)^2 = 0 (5 + 2k)(5 - 2k) = 0 5 5 k = - , - - 2 2 k = ±2.5by Tian En • 5:57 pm February 7, 2012 GMT+8:00