Find the value of k for which k^+4k+8 ,2k^+3k+6 ,3k^+4k+4
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As we know that in an AP the common difference is equal between terms
i.e
Consider an AP series:
a,a+1,a+2
Here the common difference is 1
So.
A to Q
(2k2+3k+6)-(k2+4k+8)=(3k2+4k+4)-(2k2+3k+6)
k2-k-2=k2+k-2
2k=0
k=0
i.e
Consider an AP series:
a,a+1,a+2
Here the common difference is 1
So.
A to Q
(2k2+3k+6)-(k2+4k+8)=(3k2+4k+4)-(2k2+3k+6)
k2-k-2=k2+k-2
2k=0
k=0
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