Question

find the value of k for which k + a , 2K - 1 and 2 k + 7 are consecutive terms of an ap​

Answer 1

Answer:

Given that,

k+a,2k-1 & 2k+7 are the consecutive terms of an A.P.

So, the common difference (d) would be same between them.

Therefore,

(2k-1) - (k+a) = (2k+7) -(2k-1)

2k-1-k-a = 2k+7-2k+1

k-(1+a) = 8

k = 8+(1+a)

k = a+9

Explanation:

1. always remember the consept of such questions.
2. Its rememberence depends on your practice.