Math, asked by Dev9930, 18 days ago

Find the value of K for which ‘ –K’ is zero of f(x) = x3 +kx2

-2x +k +6​

Answers

Answered by Ɍɛղgɔƙմ
2

Thanks for your question...

Your required answer :

Given :

  • -k is zero

  1. equation - +kx²
  2. equation - -2x +k +6

Solution 1 )

  • -k³ + k(-k)²
  • -k +

Solution 2 )

  • -2(-k) + k = -6
  • 2k + k = -6
  • 3k = -6
  • k = - 2

Brainliest Please

Answered by Mysteryboy01
3

 - k = 0

k = 0

1) \:  \:  {x}^{3}  + k {x}^{2}  - 2x + k + 6

 - k ^{3}  + k( - k) ^{2}  - 2( - k) + 6 = 0

 - k ^{3}  +  {k}^{3}  + 2k + k + 6 = 0

3k + 6 = 0

3k =  - 6

k =  \frac{ - 6}{3}

k =  - 2

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