find the value of k for which K X square + 12 x + 1 is equal to zero has real and distinct roots
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ATQ
Kx² + 12x +1 = 0
Here ,
a = k b = 12 c = 1
D = b²-4ac
= 12²- 4×k×1
=144-4k= 0 ( since roots are real)
= -4k = -144
K = -144/-4
= 36
The value of k is 36
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