Question

Find the value of k for which k x² + 5x – 3 = 0 has x = -3 as its root

(a) 1 (b) 2 (c) 4 (d) 6​

Answer 1

Answer:

2

Step-by-step explanation:

p(x) = kx² + 5x – 3

As x = -3 as root , substituting x in p(x) ,

p(-3) = k(-3)² + 5(-3) – 3 = 0

= 9k - 15 - 3 = 0

=> 9k - 18 = 0

=> 9k = 18

=> k = 2

Answer 2

Answer:

6

Step-by-step explanation:

K$x^{2}$+5x-3=0

k(-3)+5(-3)-3=0

-3k-15-3=0

-3k=18

k=18by3

k=6