Question

Find the value of k for which kx²-6x-2=0 has real roots

Answer 1

Step-by-step explanation:

kx ^2 - 6x -2 = 0

D = b^2 - 4 ac

(- 6 ) ^2 - 4 ( K ) ( - 2 )

36 + 8 k

8K = - 36

k = - 36 / 8

k = - 9 / 2

It has real root

2 k^2 + kx +2 = 0

tq

D = b^2 - 4 ac

( K ) ^2 - 4 ( 2 ) ( 2 )

k ^2 - 16

k^2 = 16

k = √ 16

k = 4

It has real and equal roots