Question

find the value of k for which lines kx+2y+3=0 and 8x+ky-1=0 are parallel.
​

Answer 1

Answer:

k=4

Step-by-step explanation:

since they are parallel their slopes must be equal.

Let the slope for line kx+2y+3=0 be m₁ and for line 8x+ky-1=0 be m₂

Now  Putting both the equations on the formula for standard line i.e. y = mx + c , we get:

⇒kx+2y+3=0

⇒y=(-kx-3)/2

⇒y=-kx/2-3/2...........(i)

thus,m₁=-k/2

And,

⇒8x+ky-1=0

⇒y=(-8x+1)/k

⇒y=-8x/k+1/k

Thus,m₂=-8k

Now,

since the lines are  Parallel,

m₁=m₂

⇒-k/2=-8/k

⇒-k*k=-8*2

⇒k=-16/-k

⇒k*k=16

⇒k²=16

⇒k=√16

⇒k=4

hope it helps

plz mark it as the brainliest

Answer 2

Answer:

Here is your answer...........