Question

find the value of k for which of the following equation has following roots : (k-12) x2 +2 (k-12) x+2 =0

Answer 1

Answer:

firstly, x+2=0

Step-by-step explanation:

x=-2 then, we put 2 in the place of x in eq.

so, (k-12) (-2) 2 +2k-12=0

4k-48+2k-12=0

4k+2k=48+12

4k+2k=60

6k=60

k=10

so, the value of k is 10