Question

find the value of k for which of the following quadratic equation so that the equal roots 2 X square + kx + 3 is equal to zero

Answer 1

Given :-

• Given quadratic equation: 2x² + kx + 3 = 0 has equal roots

To find :-

• Value of k for which equation has equal roots.

Solution :-

As the given equation has equal roots.So, it's discriminate = 0

We know discriminate formula :

⇒ D = b² - 4ac = 0

Comparing the given equation with ax² + bx + c we get,

• a = 2

• b = k

• c = 3

Putting values we get :

⇒ (k)² - (4 × 2 × 3) = 0

⇒ k² - 24 = 0

⇒ k² = 24

⇒ √k² = √24

⇒ k = √24

Therefore,

∴ Hence, value of k = √24 for which the given equation has equal roots.

Answer 2

Step-by-step explanation:

Given -

p(x) = 2x² + kx + 3 = 0

To Find -

Value of k

As we know that :-

• D = b² - 4ac = 0

here,

a = 2

b = k

c = 3

Now,

» (k)² - 4×2×3 = 0

» k² - 24 = 0

» k² = 24

» k = √24

• » k = 2√6

Hence,

The required value of k is 2√6.