Question

find the value of k for which one f the following systems of equation has a unique solution 2x +3y-5 = 0, kx-6y-8 =0

Answer 1

Hey....here is ur answer.
except k not equal to -4...

Answer 2

in unique solution $\frac{a1}{a2}$ $\neq$ $\frac{b1}{b2 }$
so the value of k can be whater that dont give this equal
so,  $\frac{2}{k} \neq \frac{3}{6}$
3k $\neq$ 12 
k $\neq$ 4

so k can be whatever expect 4 we can take value of k as 1,2,3,5 etc