Math, asked by neetasriv1994, 4 months ago

find the value of K for which one root of quadratic equation kx-14x+8=0 is 6 times the other​

Answers

Answered by Anonymous
1

Answer:

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Answered by khushboomudgal95
0

Answer:

let root of quadratic equation be y and 6y

y+6y= 14/k

7y = 14/k

y = 2/k

y×6y= 8/k

6y^2=8/k

6×4/k^2 =8/k

3/k =1

k=3

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