find the value of k for which one root of quadratic equation Kx2 - 14x+8=0is 2
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Answer:
K = 5
Step-by-step explanation:
Sum of zero/roots = -b/a = coff. of x / coff of x^{2}
product of zero / roota = c/a = cost. term / coff. of x^{2}
consider
3x^{2} - kx +6 = 0
a= 3
b = -k
c = 6
sum of roots = -b/a
= - (-k) / 3
= k/3
sum = 3
k/3 = 3
k = 9
Afii29:
sorry it wrrong
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