Question

Find the value of k, for which one root of the quadratic equation kx²-14x+18=0 is 3.​

Answer 1

Explanation:

For the quadratic equation kx²-14x+18 = 0,

one root is 3

So, x=3 must satisfied to the quadratic equation.

=> k(3)²-14(3) +18 = 0

=> 9k-42+18 = 0

=> 9k = 42-18

=> 9k=24

=> k=24/9

=> k = 8/3

Answer 2

Heya mate......

Kx²-14x+18=0

Where x=3

Now, put x=3

K×3²-14×3+18= 0

9k-14×3+18=0

9K-42+18=0

9k=42-18

9k=24

$k = \frac{24}{9}$

K= 8/3

Hence the value of k =8/3.