Question

find the value of k for which one root of the quadratic equqtion kx2 -14x +8=0 is six times the other.

Answer 1

on putting the value
k(6)^2-14(6)+8=0
36k-84+8=0
36k-76=0
36k=76
k=19÷9
k=2.11

Answer 2

x = 2/3 and 4 (Here 4 is 6 times of 2/3)