Find the value of k, for which one root of the quadratic equation kx2-14x+8=0 is six times the other.
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Let one zero and the other be a and 6a
a+6a=14/k
7a=14/k
a=2/k
a×6a=8/k
6a^2=8/k
6×(2/K)^2=8/k
24/k^2=8/k
K=3
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a+6a=14/k
7a=14/k
a=2/k
a×6a=8/k
6a^2=8/k
6×(2/K)^2=8/k
24/k^2=8/k
K=3
HOPE IT IS HELPFUL
MARK AS THE BRAINLIEST ANSWER
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