Question

Find the value of k, for which one root of the quadratic equation is kx^2-14x+8=0 is six times the other ​

Answer 1

Answer:

» kx² - 14x + 8 = 0

» x² - 14x/k + 8/k = 0

Let the roots be A and 6A

» A + 6A = 14/k

» A = 7/k ... (1)

» A × 6A = 8/k

» 3A² = 4/k

from (1)

» 3 (7/k)² = 5/k

» 3 (49/k²) = 5/k

» k = 147/5