Question

Find the value of k, for which one root of the quadratic equation kx2-14x+8 = 0 is 2.

Answer 1

put in b^2-4ac
where a=2k, b=14 , c=8
(14)^2-4(2k)(8)
196-64k=0
-64k=-196
64k=196
k=196/64
k=3

Answer 2

one root is 2
x=2

kx^2 - 14x + 8 = 0
4k - 28 + 8 = 0 putting [ x =2 ]
4k = 20
k = 5

i hope its help ☆☆ :)