Find the value of k for which one root of the quadratic equation kx2-14+8=0is2.answer
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Answered by
5
alpha=2
p(x) =kx2-14+8=0
p(-2)=k(-2)2-6
-4k=-6
=>k=3/2.
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p(x) =kx2-14+8=0
p(-2)=k(-2)2-6
-4k=-6
=>k=3/2.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
Answered by
10
Answer:
Step-by-step explanation:
Kx2-14x+8=0
X=2
4k-14(2)+8=0
4k-28+8=0
4k=28-8
4k=20
K=5
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