Find the value of k for which one root of the quadratic equation kxsquare-14x+8=0is2.
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p (x)=kx^2-14x+8=0
p (2)=k (2)^2-14 (2)+8=0
=4k-20=0
4k=20
k=5 answer
p (2)=k (2)^2-14 (2)+8=0
=4k-20=0
4k=20
k=5 answer
Answered by
1
my answer is in the photo
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