Question

find the value of k,for which one root of the quadratic equations kx²-14x+8=0 is 2

Answer 1

HEY THERE!!



$\huge{\bold{SOLUTION:-}}$


Given:

Equation: kx²-14x+8= 0

Also, One root of this Equation is 2

Substitute the Given value in Equation!


kx²-14x+8 = 0

k(2)² -14(2)+8 = 0

k4-28+8 = 0

4k-20 = 0

4k= 20

•°• k = 20/4

=> k = 5


Hence, Other value of this Quardratic Equation is 5

Answer 2

» here is your answer OK ☺✌

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ax2+bx+c=0
The sum of the roots is given by -ba
and the product is given by ca
Here, it is given that one of the roots is six times the other.
Let us assume one of the roots as x. Therefore, the other root will be 6x.

On comparing with the given equation, we have
x+6x=-(-14)k7x=14kx=2k....(i)

x.6x=8k6x2=8kx2=86k

Using (i), we have

2k2=86k4k2=86k
On further simplification, we obtain the value of k =3.


Hope this helps!

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