Question

Find the value of k,for which one root of the quadratic equation kx2-14x+8=0 is 2.

Answer 1

x=2
put the value of x=2 in the equation
K(2)^2-14(2)+8=0
4K - 28 +8=0
4K -20=0
4K=20
K= 20/4
K= 5

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Answer 2

P(x)=kx2-14x+8=0
Put x=2
P(2)=k(2)2-14(2)+8=0
4k-28+8=0
4k-20=0
4k=20
k=20/4
k=5