Question

find the value of K, for which one root of the quadratic equation Kx^2-14x+8=0is2.

Answer 1

k(2)^2-14(2)+8=0

k4-28+8=0

k4=28-8

k4=20

k=20÷4

k=5

Answer 2

HERE IS YOUR ANSWER :-

We know that if three numbers , say a , b , c are in A.P then b = ( a + c )/2

So x + 1 , 3x , 4x + 2 are in A.P

3x = (x +1 + 4x + 2)/2

6x = 5x + 3

x = 3

Hence the three numbers are 4, 9 , 14.

Hope this helps !


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