Find the value of k , for which one root of the quadratic equatiom kx^2-14x+8=0 is 2
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Answered by
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Answer is 5
Step-by-step explanation:
Given 2 is a root of equation thus p(2)=0.putting value of 2 in the eq
k(2)^2-14(2)+8=0
4k-28+8=0
4k=28-8
4k=20
k=5
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Answered by
0
Answer:
Step-by-step explanation:
As one root is given 2 we will put 2 at the place of x
k(2)^2 - 14(2)+8=0
k(4)-28+8=0
4k-20=0
4k=20
k=20÷4
k=5
This is wrong sorry there a mistake
After the second step
Answer:
Step-by-step explanation:
As one root is given 2 we will put 2 at the place of x
k(2)^2 - 14(2)+8=0
k(4)-28+8=0
4k-20=0
4k=20
k=20÷4
k=5
Step-by-step explanation:
As one root is given 2 we will put 2 at the place of x
k(2)^2 - 14(2)+8=0
k(4)-28+8=0
4k-20=0
4k=20
k=20÷4
k=5
Now it is right
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