Find the value of k for which one root of the quadratic equation kx-14x+8=0 is 2
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Given that, 2 is a root of the equation kx - 14x + 8 = 0. This means that when x = 2, the equation becomes zero. Thus, putting the value of x = 2 in the given equation, we get
k(2) - 14(2) + 8 = 0
2k - 28 + 8 = 0
2k = 20
k = 10
Thus, the value of k will be 10 when 2 is the root of the equation kx - 14x + 8 = 0.
k(2) - 14(2) + 8 = 0
2k - 28 + 8 = 0
2k = 20
k = 10
Thus, the value of k will be 10 when 2 is the root of the equation kx - 14x + 8 = 0.
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Question :
Find the value of k for which one root of the quadratic equation kx-14x+8=0 is 2.
Solution :
Given that one root of p(x) = kx-14x+8=0 is 2 .
And we have to find the value of k,
p(2) = k2-14(2)+8=0
2k -28 +8 = 0
2k - 20 = 0
2k = 20
k = 20/2 = 10
The required value of k is 10
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