Find the value of k, for which one root of the quadratic equation
is 2.
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dhanusri26:
=-2
it was not a very hard question
anyone can do it
no one should find a problem in this question
k=-2
yes
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Answers
Answered by
53
2×2+5 (2)(k)+16=0
=》4+10k+16=0
=》10k=-20
=》k=-2
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Answered by
104
Solution :
Equation : x² + 5kx + 16 = 0
Let f(x) x² + 5kx + 16 =0
Now, According to the Question!
Given : one root of the quadratic equation x² + 5kx + 16 =0 is 2.
Substituting the value of x in Quadratic Equation!
[ •°• f (2) = x² + 5kx + 16 =0 ]
f(x) = x² + 5kx + 16 =0
= (2)² + 5k(2) + 16 = 0
= 4 + 10k + 16 = 0
= 10k + 20 = 0
= 10k = -20
= k = -20/10
= k = -2
Hence, Value of k is -2.
Equation : x² + 5kx + 16 = 0
Let f(x) x² + 5kx + 16 =0
Now, According to the Question!
Given : one root of the quadratic equation x² + 5kx + 16 =0 is 2.
Substituting the value of x in Quadratic Equation!
[ •°• f (2) = x² + 5kx + 16 =0 ]
f(x) = x² + 5kx + 16 =0
= (2)² + 5k(2) + 16 = 0
= 4 + 10k + 16 = 0
= 10k + 20 = 0
= 10k = -20
= k = -20/10
= k = -2
Hence, Value of k is -2.
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