find the value of k for which one root of the root of quadratic equation kx 2-14x+8 =0 is 2
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Answered by
44
Answer:
Equation: kx² - 14x + 8 = 0
Also given that, one of the roots is 2.
Substituting the value of 2 instead of x we get,
⇒ k ( 2 )² - 14 ( 2 ) + 8 = 0
⇒ 4k - 28 + 8 = 0
⇒ 4k - 20 = 0
⇒ 4k = 20
⇒ k = 20 / 4
⇒ k = 5
Hence the value of k must be 5.
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AkRajput1009:
It will 100% help the guys
Answered by
51
Here is your solution
Given Equation:-
kx² - 14x + 8 = 0
one of the roots is 2
Now
putting the value of 2 in place of x we get:-
=>k ( 2 )² - 14 ( 2 ) + 8 = 0
=>4k - 28 + 8 = 0
=>4k - 20 = 0
=>4k = 20
=>k = 20 / 4
=>k = 5
Hence,
The value of k is 5.
Hope it helps you
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