Question

find the value of k, for which one zero of the quadratic polynomial kx^2-14x+8 is 2

Answer 1

$\huge {Solution -}$

$This \: is \: a \: quadratic \: polynomial \\ So, \\ \\ = > k {x}^{2} - 14x + 8 \\ = > {kx}^{2} - 14 x+ 8 = 0 \\ = > k \times ( {2)}^{2} - 14 \times (2) + 8 = 0 \\ = > 4k - 28 + 8 = 0 \\ = > 4k - 20 = 0 \\ \\ Then,\: we \: find \: the \: value \: of \: k \\ = > 4k - 20 = 0 \\ = > 4k = 20 \\ = > k = \frac{20}{ - 4} \\ = > k = \frac{5}{ - 1} \\ = > 5 \: answer$

$\huge {Be} ^ {Brainly}$

Answer 2

here ur answer .I hope it's will help u