Question

find the value of K for which point (-1 ,3) lies on the graph of the linear equation 2x-y+k=0​

Answer 1

Step-by-step explanation:

k _ 6

$2( - 1) - (3) + k$

$k = 6$

Answer 2

Answer:

k=5

Step-by-step explanation:

Here, x = -1 , y = 3

Put this value in the equation,

2(-1) - 3 + k = 0

-2 - 3 + k = 0

k = 5