find the value of K, for which Quad.
2x²+kx-4 =0 has Real Roots
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Step-by-step explanation:
Given:The equation has real roots.
DiscriminantΔ=b
2
−4ac>0 where a=1,b=−2,c=k
⇒(−2)
2
−4×1×k>0
⇒4−4k>0
⇒4(1−k)>0
⇒k−1<0
⇒k<1
∴k∈(−∞,1)
hope this helps you...plzz Mark as BRAINLIEST answer
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