Question

find the value of k for which quadratic equation 2x2-kx-k has equal root

Answer 1

$for \: equal \: roots \\ \\ d = 0 \\ \\ \ {k}^{2} - 4 \times 2 \times ( - k) = 0 \\ \\ {k}^{2} + 8k = 0 \\ \\ {k}^{2} = - 8k \\ \\ k = - 8$
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Answer 2

2x²-kx-k
a=2
b=(-k)
c=(-k)
Discriminant=0
b²-4ac=0
(-k)²-4*2*(-k)=0
k²+8k=0
k(k+8)=0
k+8=0
k=(-8)
I hope its clear to u