Question

Find the value of k for.which quadratic.equation kx² -6x -2 which has two equal roots

Answer 1

Answer:

Given:

$Equation = kx^2 -6x-2$

Solution:

For equal roots , d = 0

$\therefore d = 0$

$\implies b^2 - 4ac=0$

$\implies (-6)^2 - 4(k)(-2) = 0$

$\implies 36 + 8k = 0$

$\implies 8k = -36$

$\implies k = \dfrac{9}{2}$