Question

find the value of k for which quadratic equation kx²-kx+2=0 has equal roots​

Answer 1

Answer:

Quadratic equation has equal roots then b

2

−4ac=0

Given that kx

2

−2kx+6=0

Here a=k,b=−2k and c=6

Now, (−2k)

2

−4×k×6=0

⇒4k

2

−24k=0

⇒4k(k−6)=0

⇒k=0 or k=6

Hope it helps!

Answer 2

Answer:

Since the roots are real and equal, ∴ D = b

2 − 4ac = 0

⇒k

2 – 4×3×3 = 0 (∵ a = 3, b = k, c = 3)

⇒k

2 = 36

⇒k = 6 or −6