Question

find the value of k for which quadratic polynomial 9x^2-3kx+k has equal zeroes​

Answer 1

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Answer 2

Step-by-step explanation:

➡️QUESTION :

Find the value of k for which quadratic polynomial 9x²-3kx+k has equal zeroes.

➡️ANSWER :

The given quadratic polynomial is 9x²-3kx+k

Here ,

a = 9 ; b = -3k ; c = 1

$D = 0 \\ \\ \sqrt{ {b}^{2} - 4ac } = 0 \\ \\ \sqrt{ {( - 3k)}^{2} - 4 \times 9 \times k} = 0 \\ \\ \sqrt{ 9 {k}^{2} - 36k} = 0 \\ \\ saquaring \: both \: sides \: we \: get \\ \\ 9 {k}^{2} - 36k = 0 \\ \\ k(9 {k} - 36 ) = 0\\ \\ 9 {k} - 36 = 0 \\ \\ k \: = \frac{36}{9} = 4$

Hence ,

the value of k is 4.