Question

find the value of k for which roots of the equation x2 - 8kx + 2k =0 are equal

Answer 1

Assuming that a=x^2, and not 2x

B^2-4ac=0
(-8k)^2-(4×1×2k)=0
64k^2-8k=O
64K^2=8k
64k=8
K=8/64
=1/8

Answer 2

x^2-8kx+2k=0

d=0

b^2-4ac =0

b^2=4ac

[8]^2=4*1*2k=0

64=8k

ie.

k=64/8

k=8