Question

Find the value of k for which roots of the quadratic equation kx^2+2x+3=0 are equal

Answer 1

kx²+2x+3
a= k, b=2, c=3
D= b²- 4ac
= (2)² - 4(k)(3)
= 4 - 12k
As the roots are equal :-
4-12k = 0
12k = 4
k = 4/12
k = 1/3

Hope it helps...

Answer 2

Step-by-step explanation:

kx^2+2x+3=0

::a=k , b=2 , c=3

x=b^2-4ac

= (2)^2-4(k)(3)

=4-12k

As the roots are equal:-

4-12k=0

12k = 4

k=4/12

k=1/3 is the answer

______Abhinav Vilas Giri