find the value of k for which roots of the quadratic equation kx² + 2x + 3 = 0 are equal.
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Answered by
16
Roots Are Equal
Therefore,
b² - 4ac = 0
a = k
b = 2
c = 3
2² - 4 * 3 * k = 0
4 - 12k = 0
12k = 4
k = 4/12
k = 1/3
Therefore,
b² - 4ac = 0
a = k
b = 2
c = 3
2² - 4 * 3 * k = 0
4 - 12k = 0
12k = 4
k = 4/12
k = 1/3
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Answered by
10
kx²+2x+3=0
As the roots of the given equation are equal, D=0.
a=k, b=2, c=3
D=b²-4ac
0=2²-4(3k)
0=4-12k
12k=4
k=1/3
So the value of k is 1/3.
As the roots of the given equation are equal, D=0.
a=k, b=2, c=3
D=b²-4ac
0=2²-4(3k)
0=4-12k
12k=4
k=1/3
So the value of k is 1/3.
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