Question

find the value of k for which system equation 2kx - y =2 and 6x - 2y =3 has unique solution​

Answer 1

Answer:

for unique solu,

a1/a2 ≠ b1/b2

2k/6≠-1/-2

k/6≠1/2

k≠3

hope it helps u.....

Answer 2

Answer:

Step-by-step explanation:

2kx-y=2

6x-2y=3

ax+by+c=0

so 2kx-y-2=0

6x-2y-3=0

a1=2k        a2=6

b1= -1        b2= -2

c1= -2        c2= -3

in unique solution

a1/a2=b1/b2 is not equal to c1/c2

2k/6=-1/-2

so we get

k/3=1/2

so 2k=3

so k=3/2

hope this helped ;)