Question

find the value of k for which
${x}^{2} - kx + 3 = 0$
has 2 equal roots​

Answer 1

Heya!!

For equal Roots Descrimnant ( D ) = 0

D = (-k)² - 4 × (1)×(3)

D = 0

k² - 12 = 0

k² = 12

Taking square root on both sides.

√k² = √12

k = √ ( 4 × 3 ) OR k = -√ ( 4 × 3 )

k = √2² × √3 OR k = - √2² √3

k = 2√3 OR k = -2√3