Question

Find the value of k for which the area formed by the triangle with vertices A(4,4) B(3,k) C(3,-2) is 7 sq.units

Answer 1

Answer:

A x ( B y − C y ) + B x ( C y − A y ) + C x ( A y − B y)

4{k-(-2)} + 3{(-2)-4} + 3{4-k}=7

4(k+2) + 3(-6) + 3(4-k)=7

4k+8-18+12-3k=7

k+22=7

k=7-22

k=-15