Question

Find the value of k for which the area of triangle is 4sq.unit and hence the vertices are (-2,0) (0,4) (0,k)​

Answer 1

Answer:

it I am sure I have subscribed for peace of my mind but I'm afraid of it will

Answer 2

Answer:

The area of the triangle with vertices (k,0),(4,0) and (0,2) is given by the relation,

=

2

1

∣

∣

∣

∣

∣

∣

∣

∣

k

4

0

0

0

2

1

1

1

∣

∣

∣

∣

∣

∣

∣

∣

⇒

2

1

[−2k+8]=±4

⇒−k+4=±4

Hence, k=0,8

hope u well