Math, asked by khushishekhar23298, 1 year ago

find the value of k for which the consecutive terms 2k+1, 3k+3, 5k-1 form an AP

Answers

Answered by Anonymous

1

Answer:

3k+3=2k+1

3k-2k=1-3

k=-2

Step-by-step explanation:

Answered by RikCena

1

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