Find the value of k for which the cubic polynomial 3y³-3/2y²+ky+5 is exactly divisible(y-1/2)
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Step-by-step explanation:
y - 1/2 = 0
y = 1/2
(putting the value of y = 1/2 in the expression
3y³-3/2y²+ky+5)
3y³-3/2y²+ky+5 = 0
3(1/2)³ - 3/2(1/2)² + k(1/2) + 5 = 0
3(1/8) - 3/2(1/4) + k(1/2) + 5 = 0
3/8 - 3/8 + k/2 + 5 = 0
k/2 + 5 = 0
k/2 = - 5
k = -5 × 2
k = -10
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