Find the value of k for which the cubic polynomial is 3y^3-3/2y^2 exactly divisible by
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Answer: k=-10
Step-by-step explanation:
y=½
3x(½)³-3/2x½²+½k+5 =0
⅜-⅜+k/2+5 =0
k/2+5 =0
k/2=-5
k=-10
hope it help you
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