Question

find the value of k for which the equation 2x^2-(k-1)x+8=0 will have real and equal roots

Answer 1

Here is your answer-

Answer 2

Given,

The equation 2x²-(k-1)x+8=0 has real and equal roots.

To find,

We have to find the value of k.

Solution,

The value of k for which the equation 2x²-(k-1)x+8=0 will have real and equal roots is 9.

We can simply find the value of k by using the quadratic formula,

If the equation 2x²-(k-1)x+8=0 has real and equal roots then discriminant must be 0, then

D = b²-4ac

D = (K-1)² -4 (2)(8)

D = (K-1)²- 64

(K-1)²- 64 = 0

(K-1)² = 64

(K-1)   = 8  

    K = 8+1

   K = 9

Hence, the value of k for which the equation 2x²-(k-1)x+8=0 will have real and equal roots is 9.