Find the value of k for which the equation 3x^2-6x + k =0 has distinct and real root.
Answers
Answered by
8
Answer:
k<3
Step-by-step explanation:
For real and distinct roots,
D>0
∴b²-4ac>0
∴6²-4(3)(k)>0
∴36-12k>0
∴3>k
∴k<3
Similar questions