Question

Find the value of k for which the equation 4x^2+kx+9=0will be satisfied by only one real value of x. Also find the solution.​

Answer 1

Answer:

k = +12 & k = -12

and

real value of x= -3/2 for +k

and

x = 3/2 for -k

Step-by-step explanation:

b^2 - 4ac = 0

k^2 - 144 = 0

k = +12 & k = -12

Answer 2

Answer:

let the value be x is 1

(4*1)^2+k*1+9=0

(4)^2+k+9=0

16+k+9=0

k+25=0

k=-25