Math, asked by orangelimesoda, 7 months ago

find the value of k for which the equation 4x²-kx+1=0 has real and distinct roots​

Answers

Answered by SOUMYA2962
2

Answer:

4x²-kx+1 = 0

a= 4 b=(-k) c = 1

b²-4ac =D

D = 0

k² - 16 = 0

k² = 16

k = 4

Answered by sahithisunkari
0

Answer:

k>.+-4

if discriminant is >0 the root r real and distinct

if it is =0the roots are real and equal

if it is <0the roots are imaginary

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